When parsing text into a Timestamp object we can specify a format string. Currently %f is documented with

note that "%f" will parse all the way up to nanoseconds

See https://pandas.pydata.org/pandas-docs/stable/reference/api/pandas.to_datetime.html, in particular the description of the format parameter. The note about %f was added in this patch: https://github.com/pandas-dev/pandas/pull/8904

The fact that we can parse text using nanosecond precision is great, and here I make use of that behavior (showing two methods yielding the same result):

# Implicit format:
>>> t = pd.to_datetime('2019-10-03T09:30:12.133333337')
>>> t
Timestamp('2019-10-03 09:30:12.133333337')


# Explicit format using %f:
>>> t = pd.to_datetime('2019-10-03T09:30:12.133333337', format='%Y-%m-%dT%H:%M:%S.%f')
>>> t
Timestamp('2019-10-03 09:30:12.133333337')
````

But when I now want to invert that process using `strftime()`  then the fractional part is truncated to microsecond precision:

t.strftime('%Y-%m-%dT%H:%M:%S.%f') '2019-10-03T09:30:12.133333'


On the one hand this is inconsistent with the meaning of `%f` while parsing. On the other hand it corresponds to what's documented in Python's stdlib documentation (which says that `%f` means "Microsecond as a decimal number, zero-padded on the left.").

In any case, I think it would make sense to have a format string specifier that allows us to turn the timestamp into a string with nanosecond precision.

If I am not mistaken, we otherwise have to work around the absence of that format specifier by using the `nanosecond` property:

t.nanosecond 337

t.strftime('%Y-%m-%dT%H:%M:%S.%f') + str(t.nanosecond) '2019-10-03T09:30:12.133333337'


Do you agree that we should have a format specifier for that? Or do we have one, and it's just not documented?



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------------------
commit           : None
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**Comment From: jgehrcke**

Note to self: interestingly, I just saw that Ruby's strftime has a `%N - Fractional seconds digits, default is 9 digits (nanosecond)`: https://ruby-doc.org/core-2.6.4/Time.html, and Go has no strftime, but a property `https://golang.org/pkg/time/#Time.Nanosecond` that can be zero-padded.

Another note to self: `Timestamp.timestamp()` returns microsecond precision, instead of nanosecond precision: 

t = pd.to_datetime('2019-10-03T09:30:12.133333337') t.timestamp() 1570095012.133333


Third note to self: for the specific format I want to emit in my example above there is this working shortcut: `t.isoformat()` yields `'2019-11-07T12:29:23.444348736'`.

**Comment From: matteosantama**

Ran into this issue today. Proposed solution is to add `.strftime()` method to `Timestamp` object in `pandas/_libs/tslibs/timestamps.pyx`. 

Is the best route to fully reimplement the method? I think ideally it would look something like this

```python
def strftime(self, fmt: str) -> str:
    if self.nanosecond == 0:
        return super.strftime(fmt)

    # else 

but I can't think of an elegant else clause (outside of reimplementing the entire method).

Comment From: AlexeyDmitriev

1) I don't think that you need the if. Because user may need to output all 9 digits even if zeros are here 2) You can avoid implementing the whole method this way: (supposing %9 to print 9 digits of nanoseconds) You find all %9's (but you need to parse it carefully, e.g. "%%9" is literal percent sign, then literal 9), then replace them all with nine digits of nanoseconds. Then pass the resulting string to the datetime.strftime

Comment From: AlexeyDmitriev

@jgehrcke

Third note to self: for the specific format I want to emit in my example above there is this working shortcut: t.isoformat() yields '2019-11-07T12:29:23.444348736'. The problem with your shortcut through is that if t accidentally is whole number of microseconds, the last 000 are not printed

Comment From: smarie

Note that for Periods there is a different convention in pandas: %u means microseconds and %n means nanoseconds. This is mostly because for such objects, %f means "fiscal year".